Kinematic Chains, Joints, Degree of Freedom and GRUBLER’S RULE
KINEMATICS CHAINS
Kinematic chain: A kinematic chain is a group of links either joined together or arranged in a manner that permits them to move relative to one another. If the links are connected in such a way that no motion is possible, it results in a locked chain or structure.
Fig.1.16 Locked chain or structure
TYPES OF JOINTS
The usual types of joints in a chain are
• Binary joint
• Ternary joint
• Quaternary joint
Binary Joint: If two links are joined at the same connection; it is called a binary joint. For example. Fig. 1.17 shows a chain with two binary joints named B.
Ternary Joint: If three links are joined at a connection, it is known as a ternary joint. It is considered equivalent to two binary joints since fixing of any one link constitutes two binary joints with each of the other two links. In Fig. 1.17 ternary links are mentioned as T.
Fig 1.17
Quaternary Joint: If four links are joined at a connection, it is known as a quaternary joint. It is considered equivalent to three binary joints since fixing of any one link constitutes three binary joints. Figure 1.17 shows one quaternary joint.
In general, if ‘n’ number of links are connected at a joint, it is equivalent to (n1) binary joints.
DEGREE OF FREEDOM
Degrees of freedom (DOF): It is the number of independent coordinates required to describe the position of a body in space. A free body in space (fig 1.18) can have six degrees of freedom. i.e., linear positions along x, y and z axes and rotational/angular positions with respect to x, y and z axes.
In a kinematic pair, depending on the constraints imposed on the motion, the links may lose some of the six degrees of freedom.
Fig.1.18
Possible Motions:
1. Three translations along x, y and z axes.
2. Three rotations about x, y and z axes.
So an object in free space has six degrees of Freedom.
A fixed object has zero degree of freedom.
GRUBLER’S RULE
Degrees of freedom/mobility of a mechanism: It is the number of inputs (number of independent coordinates) required to describe the configuration or position of all the links of the mechanism, with respect to the fixed link at any given instant.
Grubler’s equation: Number of degrees of freedom of a mechanism is given by
F = 3(n1)2lh. Where,
F = Degrees of freedom
n = Number of links = n_{2} + n_{3} +……+n_{j}, where, n_{2} = number of binary links, n_{3} = number of ternary links…etc.
l = Number of lower pairs, which is obtained by counting the number of joints. If more than two links are joined together at any point, then, one additional lower pair is to be considered for every additional link.
h = Number of higher pairs
Examples of determination of degrees of freedom of planar mechanisms:
(i)
F = 3(n1)2lh Here, n_{2} = 4, n = 4, l = 4 and h = 0. F = 3(41)2(4) = 1 I.e., one input to any one link will result in definite motion of all the links.

(ii)
F = 3(n1)2lh Here, n_{2} = 5, n = 5, l = 5 and h = 0. F = 3(51)2(5) = 2 I.e., two inputs to any two links are required to yield definite motions in all the links. 
(iii)
F = 3(n1)2lh Here, n_{2} = 4, n_{3} =2, n = 6, l = 7 and h = 0. F = 3(61)2(7) = 1 I.e., one input to any one link will result in definite motion of all the links.

(iv)
F = 3(n1)2lh Here, n_{2} = 5, n_{3} =1, n = 6, l = 7 (at the intersection of 2, 3 and 4, two lower pairs are to be considered) and h = 0. F = 3(61)2(7) = 1

(v)
F = 3(n1)2lh Here, n = 11, l = 15 (two lower pairs at the intersection of 3, 4, 6; 2, 4, 5; 5, 7, 8; 8, 10, 11) and h = 0. F = 3(111)2(15) = 0 
(vi) Determine the mobility of the following mechanisms.
(a)
F = 3(n1)2lh Here, n = 4, l = 5 and h = 0. F = 3(41)2(5) = 1 I.e., it is a structure

(b)
F = 3(n1)2lh Here, n = 3, l = 2 and h = 1. F = 3(31)2(2)1 = 1 
(c)
F = 3(n1)2lh Here, n = 3, l = 2 and h = 1. F = 3(31)2(2)1 = 1

14 Responses to “Kinematic Chains, Joints, Degree of Freedom and GRUBLER’S RULE”
Dilanka Deegala
Nice explanation.Appreciate a lot
admin
Thanks for the appreciation.
viren
awesome work …helped me a lot!!
admin
Thanks….
Ishan A Chavan
Awesome! Got a total understanding about the topic! Excellent.
sandeep
excellent work. not many people can explain this like you did.
Sunil
Sir can we get still more problems…. Which would be beneficial for us
nimesh chandra
really awesome…now everything on this topic seems cool..really appreciable
Rohit
Thanks for to remove my confusions.
KUNDAN
NICE WAY AND EXAMPLE
KUNDAN
NICE WAY AND EXAMPLES
umar
Y we write 3in formula plz explain
devendra
I want to know relation between nu. of links joint and pairs
Prakash thakur
THANKS A LOT…..